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SOLVED: Experiment VIII- Determination of Calcium Carbonate in eggshells mass of eggshell = 0.9 Total amount of HCl = 250ml, 1.0 moVL Volume of HCI used = 30 ml NaOH titrant 0.15 M Ph Ph or Bromophenol blue as indicatorCalculate the Total amount of HCI =Calculate the moles of excess HCI:HCLNaOH M =0. moVLNaCLH,oAverage V NaOH10 mlMol NaOHMol excess HCL iu 25 mlMol excess HCI in 250 mlCompensate in the equation:Mol HCI ReactedTotal mole HCL (1) Excess mole HCI (2)Calculate the mass of CaCOz in th

SOLVED: Experiment VIII- Determination of Calcium Carbonate in eggshells mass of eggshell = 0.9 Total amount of HCl = 250ml, 1.0 moVL Volume of HCI used = 30 ml

VIDEO ANSWER: To calculate the percentage mass of calcium carbonate in x, shell, we need the data which is given to us and the weight of all of it. We have 100…

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SOLVED: Experiment 1: Gravimetric Analysis with Calcium Chloride and Potassium CarbonateData SheetTable 1: Data and ObservationsMaterial Mass CaCl2 2.0g K2CO3 2.5g Filter Paper 2.2g Watch Glass 35.1g Filter Paper Watch Glass Precipitate 42.4g Precipitate 3.0g Table 2: Mass of CaCl2 after 24 HoursInitial Observations 24-hour Observation Weigh Boat 2.4g 2.2g CaCl2 2.0g 4.2g Analyze the data and use your yield of calcium carbonate to determine the experimental concentration of calcium chloride

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