2016年2月17日 · Vertical asymptote at x=-1. No horizontal asymptotes. Vertical asymptote at places which make the denominator zero, ie when x=-1. Horizontal asymptotes at lim_(x->+ …

y=8x+2 Tangent Line to a Curve simplify y=x^3-2x^2+x-2 differentiate y'=3x^2-4x+1 substitute for x=-1 y'=8 the value of y' is the slope of the tangent line at x=-1 and to get the point which lies …

2018年4月8日 · 2 real solutions You can use the discriminant to find how many and what kind of solutions this quadratic equation has. Quadratic equation form: ax^2+bx+c, in this case a is 2, …

2016年12月12日 · x+1/(2(x-1)) +1/(2(x+1)) How do you write the partial fraction decomposition of the rational expression # (3x^2 + 12x -...

2016年5月27日 · Testing the endpoints of the intevral and the critical number in the interval, we find: f(0) = 0 f(1) = 1 f(3) = 3/7 So, absolute minimum is 0 (at x=0) and absolute maximum is 1 …

2018年3月24日 · x = (-1 ± isqrt(3))/2 Use the quadratic formula : x = (-b ± sqrt(b^2 - 4ac))/(2a) x = (-1 ± sqrt(1 - 4(1)(1)))/(2(1)) x = (-1 ± sqrt(-3))/2 x = (-1 ± isqrt(3))/2

2015年9月25日 · It is (x^2+2x+1)/(x+1)=(x+1)^2/(x+1)=(x+1) 8993 views around the world You can reuse this answer

2017年10月20日 · y = 3(x-1) + 1 STEP 1: Identify the rules needed to derive the function. For this equation, both the Chain Rule and Product Rule will be needed.

2017年12月7日 · x=pi To solve an equation like this, it is helpful to have only one trig function so we can solve for it and then solve for x. In this case it is easiest to use cosx. First, we can use …

2015年4月13日 · Another way of doing this is to consider that #d(secx) = secxtanx*dx#. That is, the derivative of #secx# is #secxtanx#