How do you integrate Sinx * Tanx? | Socratic
2016年12月9日 · The answer is =ln (∣tanx+secx∣)-sinx +C We need, secx=1/cosx cos^2x+sin^2x=1 tanx=sinx/cosx (tanx)'=sec^2x (secx)'=tanx secx …
What is the derivative of -cosx*ln (secx+tanx)? | Socratic
Just do the product rule, followed by the chain rule (on only the ln (u)). Recall that d/ (dx) [cosx] = -sinx, and that d/ (dx) [ln (u (x))] = 1/ (u (x)) (du (x ...
Tanx/1-cotx+cotx/1-tanx=? - Socratic
2018年3月29日 · tanx 1 − cotx + cotx 1 −tanx = tanx(− tanx) (1 − cotx)(−tanx) + cotx 1 − tanx = −tan2x 1 − tanx + cotx 1 −tanx [∵ tanx ×cotx = 1] = cotx −tan2x ...
How do you evaluate the integral (secx tanx) / (sec^2 (x) - Socratic
2018年5月10日 · How do you evaluate the integral sec x tan x sec2(x) − sec x dx?
How do you use logarithmic differentiation to find the derivative of
2015年3月27日 · How do you use logarithmic differentiation to find the derivative of y = (tan x) 1 x?
How do you graph y=tanx? | Socratic
graph{tan x [-10, 10, -5, 5]}. See explanation. graph{tan x [-10, 10, -5, 5]} The number of lines you have to draw depends on the domain provided. If the domain is not specifically provided, you …
If tanx=sqrt2, then find sinx and cosx? | Socratic
2017年8月23日 · Either sinx=sqrt (2/3) and cosx=1/sqrt3 or sinx=-sqrt (2/3) and cosx=-1/sqrt3 As tanx=sqrt2 secx=+-sqrt (1+ (sqrt2)^2)=+-sqrt3 and hence cosx=+-1/sqrt3 …
How do you prove (tanx+cotx)/ (secx+cscx)=1/ (cosx+sinx
How do you prove tan x + cot x sec x + csc x = 1 cos x + sin x?
How do you find the general solutions for tanx+1=0? | Socratic
2015年9月23日 · Refer to explanation It is tanx+1=0=>tanx=-1=>tanx=tan (-pi/4)=> x=k*pi-pi/4 The general solutions are x=k*pi-pi/4 where k belongs to integers
Prove that tanx/ (1+secx)+ (1+secx)/tanx=2secx? | Socratic
2016年2月23日 · Perhaps what you mean is to prove that tanx 1 +secx + 1 + secx tanx = 2cscx. To solve this let us start from LHS and prove using other identities that this is equal to RHS.