2017年12月31日 · #sqrt(x-3)=y# #larr# This is the inverse function denoted by as #f^(-1)(x)# Given #sinhx=(e^x-e^-x)/2# , finding it's inverse is the same concept: Suppose #y=sinhx# , so …

2018年2月10日 · The higher order derivatives of #sinh(x)# will either be #sinh(x)# or #cosh(x)#. If we consider the definitions for them, we see that #cosh(x)# will always be larger than …

2018年3月8日 · 1/4cos2h(x)+C int sinh(x)*cosh(x)*dx =1/2int sin2h(x)*dx =1/4cos2h(x)+C

2016年3月3日 · The answer above that uses the limit #lim_{x rarr 0} {sin x}/x# also is invalid (using the criteria indicated by the note) because this limit cited needs also L'Hôpital's rule to …

f(x) = 2x + (2x^3)/3 + x^5/(20) + x^7/(630) + ... \ \ \ \ x in RR There are several ways to develop a solution, we could start from first principles and form the Taylor series for the hyperbolic …

2015年10月31日 · 4sinh^3x*coshx By using the power rule and rules for differentiation for hyperbolic trig functions we get d/dxsinh^4x=4sinh^3x*coshx

2018年5月16日 · -xe^(-x)-e^(-x)+C int x/(sinhx+coshx)*dx =int x/(e^x)*dx =int xe^(-x)*dx =x*(-e^(-x))-int (-e^(-x))*dx =-xe^(-x)+int e^(-x)*dx =-xe^(-x)-e^(-x)+C

2016年5月5日 · How do you prove #(1-\cos^2 x)(1+\cot^2 x) = 1#? How do you show that #2 \sin x \cos x = \sin 2x#? is true for #(5pi)/6#? How do you prove that #sec xcot x = csc x#?

#I = int \ cosx \ coshx \ dx# #= int \ cosx \ d(sinh x)# #= cosx sinh x - int \ d( cosx) \ sinh x# #= cosx sinh x + int sin x \ sinh x \ dx#

2017年7月24日 · We seek: # I = int \ ln tanh(x/2)/cosh^2x \ dx # I will take a very similar approach to that of Truong-Son N. but I will simplify the expression in the integrand via an initial …