
What is the sin cos and tan of 45? - Socratic
What is the sin cos and tan of 45? Trigonometry Right Triangles Trigonometric Functions of Any Angle. 1 ...
How do you solve #Sin45 = 12/x - Socratic
Sep 29, 2015 · 12*sqrt(2) sin 45=1/sqrt(2) 1/sqrt(2)=12/x x=12*sqrt(2)
How do you find the exact value of - Socratic
Use trig identity: sin (a - b) = sin a.cos b - sin b.cos a Trig table --> #sin 45 = sqrt2/2# and #cos 30 = sqrt3/2#
How do you simplify #cos(45^@+a)cos(45^@-a)-sin(45^@-a)sin …
May 10, 2018 · 0 Yes, it simplifies to give you zero. Now to make our lives easier, it would be better to turn the equation to: cos(45+a)cos(45-a) = sin(45-a)sin(45+a) This way we can resolve both sides without things getting mixed and muddled together. You should be comfortable with your trigonometric identities so by looking at this equation you are able to tell the four identities …
Derivative of cos(45)? - Socratic
May 30, 2018 · -sin(45) In general, you can remember the fact that, d/dxsin(x)=cos(x) and d/dx cos(x)=-sin(x) So we have, d/dxcos(x) = -sin(x) => d/dxcos(45) = -sin(45) Hence the ...
How do you evaluate #sin(-135)#? - Socratic
Nov 14, 2015 · Evaluate sin (-135) Ans: -sqrt2/2 Trig Table of Special Arcs and unit circle give: sin (-135) = sin (45 - 180) = - sin (45) = -sqrt2/2
How do you find the angle of the sum and difference ... - Socratic
Jul 23, 2018 · How do you evaluate #sin(45)cos(15)+cos(45)sin(15)#? How do you write #cos75cos35+sin75sin 35# as a single trigonometric function? How do you prove that #cos(x-y) = cosxcosy + sinxsiny#?
How do you write the complex number z = 6(cos 45° + i sin 45°) in ...
Feb 21, 2016 · How do I convert the polar coordinates #3(cos 210^circ +i\ sin 210^circ)# into rectangular form? What is the modulus of the complex number #z=3+3i#? What is DeMoivre's theorem?
What are the cosecant and secant of 45 degrees? | Socratic
May 3, 2015 · Trig conversion table gives: cos 45 = (sqr2)/2 -> sec 45 = 1/cos 45 = 2/(sqr2) sin 45 = (sqr2)/2 -> csc 45 = 1/sin 45 = 2/(sqr2)
Find the value of #sin(120^@-45^@)#? - Socratic
Mar 31, 2017 · sin(120^@-45^@)=(sqrt3+1)/(2sqrt2) sin(A-B)=sinAcosB-cosAsinB Here if A=120^@ and B=45^@, we can find sin(120^@-45^@), but we need to know sine and cosine ratios of the two angles.