Find the limit of ln(n)/ln(n+1) as n--> infinity - Physics Forums
2008年10月26日 · can someone help me find the lim as n approaches infinity of ln(n)/ln(n+1) I used L'HOP so it became (1/n)/(1/n+1) -- as this approaches infinity... Insights Blog -- Browse All Articles -- Physics Articles Physics Tutorials Physics Guides Physics FAQ Math Articles Math Tutorials Math Guides Math FAQ Education Articles Education Guides Bio/Chem ...
Is ln(-1) Equal to Zero? - Physics Forums
2007年3月6日 · Actually, that step is perfectly valid in general - (a/a) ln(x) = 1/a ln(x^a), i.e. when everything is defined. Your next line explains why it's not valid here: If you look at the logarithm graph, you will see that the function is not defined for negative x.
Limit of ln(n)/ln(n+1) as n->+infinity, very confusing - Physics …
2008年10月27日 · Limit of ln(n)/ln(n+1) as n-->+infinity, very confusing can someone help me find the lim as n approaches infinity of ln(n)/ln(n+1) I used L'HOP so it... Insights Blog -- Browse All Articles -- Physics Articles Physics Tutorials Physics Guides Physics FAQ Math Articles Math Tutorials Math Guides Math FAQ Education Articles Education Guides Bio ...
How do you simplify #Ln(-e) - ln(-1/e)#? - Socratic
2016年3月23日 · This expression is not valid because #ln# function is only defined for positive numbers. Explanation: This expression is not valid because #ln# is not defined for negative numbers but if it was:
Converging or diverging 1/ln(n) - Physics Forums
2010年1月9日 · Determine if the series n=2 to inf. of 1/ln(n) converges or diverges Ok so first I tried the limit test (the simple one) and found that it was 0 which... Insights Blog -- Browse All Articles -- Physics Articles Physics Tutorials Physics Guides Physics FAQ Math Articles Math Tutorials Math Guides Math FAQ Education Articles Education Guides Bio ...
What Connects the Natural Logarithm of i with Pi? - Physics Forums
2011年1月31日 · Why does ln(i) = (1/2pi)i? I was bored the other day and wondered whether or not it would be possible to find out the natural log of the imaginary number i. Typed it into my TI-84 and it said the answer was 1.57079632i. I wondered why the might be the case, thought about it for a while and...
Convergence of series log(1-1/n^2) - Physics Forums
2018年9月14日 · $$\ln\prod_{n=2}^{\infty} \frac{(n-1)(n+1)}{n^2}$$ So you can work with that product instead and prove that the product is equal to ##\frac{1}{2}## so the limit is ##\ln\frac{1}{2}=-\ln2## I know that usually is not a good idea …
Maclaurin Series for ln(1+e^x) and \frac{x}{(e^x-1)} - Physics Forums
2005年10月29日 · obtain the maclaurin series expansions of the following: ln(1+e^x) ok I am quite lost..i assume you set it equal to f(x) then differentiate..but what... Insights Blog -- Browse All Articles -- Physics Articles Physics Tutorials Physics Guides Physics FAQ Math Articles Math Tutorials Math Guides Math FAQ Education Articles Education Guides Bio ...
What's the UNIT after you take the natural log? - Physics Forums
2007年3月20日 · The units of a ln(p) would generally be referred to as "log Pa" or "log atm." Taking the logarithm doesn't actually change the dimension of the argument at all -- the logarithm of pressure is still pressure -- but it does change the numerical value, and thus "Pa" and "log Pa" should be considered different units.
MacLaurin Series for f(x)=ln|1+x^3| - Physics Forums
2010年5月19日 · then find out why appx'ing integral of ln|1+x^3| from 0 to 2 by using the series representation is wrong. but i think i can figure those out once the first part is done. Last edited: May 19, 2010