2016年10月20日 · What is the derivative of #cos( sin( x ))#? Calculus Basic Differentiation Rules Chain Rule. 1 Answer

2018年5月7日 · #sin^{-1}(x)#, which I prefer to denote #arcsin(x)#, refers to every inverse sine, not just the principal value, which I denote #text{Arc}text{sin}(x).# #cos theta# where #theta = …

2017年2月4日 · cos(sin^(-1)(sqrt(3)/2)) = 1/2 Consider an equilateral triangle with sides of length 2, bisected to form two right angled triangles: Remembering that sin = …

2018年3月20日 · :. sin 45 cos 15 + cos 45 sin 15 = sin (45 + 15) = sin 60 = sqrt 3/2 sin 45 cos 15 + cos 45 sin 15 It is in the form sin a cos b + cos a sin b But we know sin (a + b ...

Here is an example of using a sum identity: Find #sin15^@#.. If we can find (think of) two angles #A# and #B# whose sum or whose difference is 15, and whose sine and cosine we know.

2016年5月19日 · Let #a = sin^(-1) (-3/5)#. Then, #sin a = -3/5<0#. So, a is in the 3rd quadrant or in the 4th. Accordingly, cos a = (- or +)(4/5). Let #b = cos^(-1) (3/5)#. Then, #cos b = 3/5>0.# …

2018年3月19日 · To prove that #cos^4x-sin^4x=1-2sin^2x#, we'll need the Pythagorean identity and a variation on the Pythagorean identity: #color(white)=>cos^2x+sin^2x=1# #=>cos^2x=1 …

2016年5月27日 · cot(x) cos(x)/sin(x) = cot(x) How do you apply the fundamental identities to values of #theta# and show that they are true?

2016年8月29日 · The given expression is cos a =sqrt(1-sin^2 a) =sqrt(1-(-1/4)^2) =sqrt 15/4. Instead of the principal a or any other value in Q4, if we choose a value in Q3, wherein cosine …

2015年8月20日 · (sinX-cosX)^2 = 1-sin2X sin^2 A + cos^2 A = 1 sin 2A = 2 sin A cos A (sinX-cosX)^2 = sin^2 X -2sin X cos X + cos^2 X = 1-2sin XcosX = 1-sin2X