2016年11月29日 · Cr(CO${_3}$)${}_3$ This is an ionic compound. Chromium is a transition metal cation and CO${_3}$ is an anion with a charge of 2-, as said in my chemistry textbook. And since CO${_3}$ has a charge of 2-, the over all charge of CO${_3}$ would be 6-, since it has a subscript of 3 in the bolded formula above. So my guess is that since Chromium has ...

2020年10月6日 · In principle it could be obtained according to $$\ce{2 Cr^{3+} + 3 CO3^{2-} -> Cr2(CO3)3}$$ But like with the aluminum and ferric carbonates, the chromium carbonate is immediately destroyed according to : $$\ce{Cr2(CO3)3 + 3 H2O -> 3 CO2 + 2 Cr(OH)3}$$ As a consequence, chromium carbonate does not exist in aqueous solutions and, if carbonate ...

2018年4月17日 · The chloride-ligands exchange for water ligands like $\ce{[Cr(H2O)5Cl]Cl2 * H2O}$ which is blue-green. And in the end the $\ce{[Cr(H2O)3Cl3]*(H2O)3}$ is green. Some ions like fluoride are said to influence this process but I have not been able to confirm that yet.

2020年11月21日 · The complex of $\ce{Cr}$ with three oxalate ions must compensate the charges of the cobalt complex (+ $2$ or + $3$). So the charge of the chromium complex has to be - $2$ or - $3$. In other words, the complex ion is either $\ce{[Cr(C2O4)3]^{2-}}$ or $\ce{[Cr(C2O4)3]^{3-}}$.

2017年9月24日 · 1.10 * 10^(24) The first thing that you need to do here is to convert the mass of aluminium carbonate to moles by using the compound's molar mass. In this case, you know that aluminium carbonate has a molar mass of "233.99 g mol"^(-1), which means that 1 mole of aluminium carbonate has a mass of "233.99 g". You can thus say that your sample will contain 47.6 color(red)(cancel(color(black)("g ...

2018年3月17日 · 1) Cr3+ has 3 electrons in 3d orbital. Obviously, it is a tetrahedral splitting, so configuration will be eg2 t2g1 which shows it is paramagnetic. 2) Here you need to know that for Co3+ all complexes are low spin except [CoF6]3- and [Co(H2O)3F3]. So, the complex given will be low spin with all 6 electrons paired & thus it will be diamagnetic.

2021年5月26日 · According to the above rules, the oxidation state of cobalt in the complex can be written in two ways - as (III) or (3+). Similarly the chloride ions can be named in two different ways - chloride or dichloride.

2016年2月12日 · Hence, $\ce{Mn^3+}$ is a good oxidising agent. The hydration enthalpy of $\ce{Cr^3+}$ is anomalously large (for a 3+ ion) because there is a large ligand-field stabilisation energy associated with the $(t_{2g})^3$ configuration. (This is factor number 2, not factor number 1). Hence, $\ce{Cr^2+}$ is a reducing agent.

2018年5月15日 · It suggests that $\ce{Fe^3+}$ should be the most stable, but the answer key given for increasing stability instead is $\ce{Co^3+ < Fe^3+ < Cr^3+ < Sc^3+}$. This seems to suggest that lower number of d-electrons leads to more stability, but I am not sure why that is true.

2022年1月9日 · 3 $\begingroup$ Then better to express it particularly as strong/weak oxidant/reductant. As another meanings can be thermodynamic or kinetic stability toward hydrolysis. $\endgroup$