2024年1月9日 · FizzBuzz是一个常见的编程入门挑战，要求编写一个程序，它能遍历从1到N的整数，对于能被3整除的数字打印"Fizz"，能被5整除的打印"Buzz"，同时能被3和5整除的打印"FizzBuzz"，对于其他数字则打印数字本身。

Transcribe and translate audio offline on your personal computer. Powered by OpenAI's Whisper. Buzz is better on the App Store. Get a Mac-native version of Buzz with a cleaner look, audio playback, drag-and-drop import, transcript editing, search, and much more. Install ffmpeg. Install Buzz. Install with brew utility.

Buzz是一款基于OpenAI Whisper模型构建的离线语音转文字工具，适用于Windows、macOS和Linux系统。 Buzz能将麦克风输入或音频、视频文件实时转换为文字，支持多种格式导入导出，如TXT、SRT和VTT。

2015年4月11日 · This takes advantage of the fact that you know there are no % characters in "fizz" or "buzz". It's guaranteed to be safe to pass unused args to printf. To make the source readable, pull the logic to select a format string out of the printf() itself, and store it …

2025年2月7日 · Fizz Buzz problem states that given an integer n, for every integer i <= n, the task is to write a C++ program to print, 'FizzBuzz' if i is divisible by 3 and 5, 'Fizz' if i is divisible by 3, 'Buzz' if i is divisible by 5'i' as a string, if none of the conditions are true.Example: Input: n = 3Ou

2023年2月8日 · Buzz 是一款开源的语音转文字工具，它能够实时将语音转换为文字，支持多种操作系统，包括 Windows、macOS 和 Linux。 它不仅支持实时 语音识别 ，还能将视频和音频文件 转 换成 文字 或字幕，极大地方便了内容创作者、翻译工作者和广大用户。

2025年1月20日 · 给你一个整数 n ，找出从 1 到 n 各个整数的 Fizz Buzz 表示，并用字符串数组 answer （下标从 1 开始）返回结果，其中： answer[i] == "FizzBuzz" 如果 i 同时是 3 和 5 的倍数。 answer[i] == "Fizz" 如果 i 是 3 的倍数。 answer[i] == "Buzz" 如果 i 是 5 的倍数。 answer[i] == i （以字符串形式）如果上述条件全不满足。 示例 1： 示例 2： 示例 3： 提示： 我的代码： vector <string> fizzBuzz(int n) { . vector <string> ans; for (int i = 1; i <= n; ++ i) { .

FizzBuzz Program in C is a simple programming task used in software developer job interviews. It is often used as an initial screening question to help filter out candidates who lack basic coding skills. In this task, you are asked to write a program that prints the numbers from 1 to 100.

Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output...

The Fizz Buzz program's objective is to repeatedly loop through a list of integers and apply a set of rules to decide what to output for each number. These are the guidelines: Whenever a number is divisible by 3, "Fizz" is output in its place. Whenever a number is …