2017年4月5日 · $ toilet -f letter ABC A BBBB CCC A A B B C C AAAAA BBBB C A A B B C C A A BBBB CCC That letter font is a figlet font that comes with the toilet-fonts package on Debian at least. After that package is installed, you can also use that font with figlet (figlet -f letter).

2021年11月18日 · Just the inclusion of the ? is enough for Raku to know to stop at the appropriate spot nearest the left-end of the consecutive-B run (the B**4 regex tells Raku to search for 4-consecutive Bs). That's the simplest solution.

2018年6月12日 · Locale locale locale. You get unexpected results because your default locale is something other than C or C.UTF-8.

> X="aaaa" > echo ${X//a/b} # substitute all occurences of a with b > bbbb Thus in your first example your parameter was "a/b" and you told bash to replace the first occurence of "b" in "a/b" (the value of var) with the string "c/d" (which results in "a/c/d"). Note that "\d" is unnecessarily escaped - no difference to "d" alone).

2019年6月14日 · FIELD1 FIELD2 FIELD3 FIELD4 aaaa aaaa aaaa aaaa bbbb bbbb bbbb bbbb cccc cccc cccc cccc I guess that if I can fix a row like ROW2, fixing ROW3 would be similar but I can't understand how to have some tool like awk or sed see more than one row at a time and, for example, replace "\n\s*bbbb" with " bbbb" and fix ROW2. EDIT:

2015年5月5日 · AAAA 1234 BBBB 5678 CCCC 9012 DDDD 3456 EEEE 7890 Share. Improve this answer. Follow

2 aaaa 1 bbbb 3 cccc 4 dddd It is close to what I want to achieve, but my desired result is: 2 aaaa 1 bbbb 3 cccc 4 dddd 0 eeee 0 ffff So the problem is: how to print '0' if a line from pattern.in file is not matched? It needs to be done in a simplest possible way, as all I …

2018年4月11日 · aaaa:bbbb:cccc:dddd:eeee:ffff:gggg:hhhh[%int][/netmask] netmask works the same as IPv4, except that it can go up to 128. The %int is required for scoped addresses, which are not global addresses and only have meaning inside a local network, and specifies which network interface owns the address as two interfaces may have the same address.

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grep -B 1 '&$' your_file This will look for lines ending in &, remove $ to match lines with & anywhere in them. The -B switch tells grep to output "context" lines that come before the lines that match. In this case, since you want one line of context, you need -B 1. This switch is available in GNU grep but is not in the POSIX standard, though.