
How do you solve -2<=x-7<=11? | Socratic
2016年8月3日 · The first thing to do here is get x alone in the middle of the compound inequality by adding 7 to all three sides −2 + 7 ≤ x − 7 ≤ 11 + 7 aaaaa5 ≤ aaxaa ≤ 18 You now know that in order to be part of the solution interval, a value of x must satisfy two conditions x ≥ 15 → the left side of the compound inequality x ≤ 18 → the right side of the compound inequality For the ...
How do you solve x^3+7x^2-x-7<0? | Socratic
2017年1月29日 · The answer is x in ]-oo, -7 [uu]-1, 1 [ Let f (x)=x^3+7x^2-x-7 f (1)=1+7-1-7=0 so, (x-1) is a factor of f (x) To find the other factors, we do a long division color ...
2x^3-7x^2-2x+7? How to factor it completely? | Socratic
2018年5月8日 · From the coefficients, you can tell that x = 1 will make the equation equal to zero. 2(1)3 −7(1)2 − 2(1) +7 = 0 Then you do a polynomial divsion of 2x3 −7x2 −2x +7 x + 1 (Don't know how to format this so I wrote it out and took a picture of it) 2x3 − 7x2 − 2x + 7 …
How do you expand (2y^2+x)^7? | Socratic
2017年10月4日 · (2y^2+x)^7= 128 y^14+448 x y^12+ 672 x^2 y^10 + 560 x^3 y^8 + 280 x^4 y^6+ 84 x^5 y^4+ 14 x^6 y^2+ x^7 When expanding an expression like this, knowing Pascal's Triangle is crucial: (Source) Since this expression is of degree 7 (i.e. has highest power 7), there will be 8 terms in the expansion (like in a quadratic equation where the highest power is 2, there are 3 terms). As you can see, the ...
How do you solve 2x^2 + x + 7 = 0? | Socratic
2016年3月9日 · The solutions are: x= (-1+sqrt (-55))/4 x= (-1-sqrt (-55))/4 2x^2 + x+7=0 The equation is of the form color (blue) (ax^2+bx+c=0 where: a=2, b=1, c=7 The Discriminant ...
How do you solve 4x-2=x+7? | Socratic
2018年3月6日 · Solving linear equations requires you to use the "balance method". 4x −x −2 = x −x +7 3x −2 +2 = 7 +2 3 x 3 = 9 3 x = 3
How do you solve (x+4) (x-2) (x-7)>0? | Socratic
2016年7月21日 · The three zeros of function (x + 4)(x − 2)(x −7) divide real number line in four parts (1) x <− 4 - Here all the terms are negative, hence f (x) is positive.
How do you solve 2(x+7)+x=20? | Socratic
Apply the distributive property 2x +2 ⋅ 7 + x = 20 Multiply by 7 to get 14 2x +14 + x = 20 Add 2x and x to get 3x 3x +14 = 20 Since 14 does not contain the variable to solve for, move it to the right side of the equation by subtracting 14 from both sides. 3x = −14 + 20 Add −14+ 20 to get 6 3x = 6 Divide each term by 3 and simplify. Answer ...
How do you find all zeros with multiplicities of f (x)=x^3-7x^2+x-7 ...
2017年9月17日 · The zeros of f (x) are 7, i, -i, all with multiplicity 1. Given: f (x) = x^3-7x^2+x-7 Note that the ratio between the first and second terms is the same as that between the third and fourth terms.
What is the vertex form of f (x) = -2x^2+7x-12 ? | Socratic
Given the standard form of a parabola: f (x) = ax2 + bx +c The vertex form is: f (x) = a(x − h)2 +k Please see the explanation for the conversion process.