2018年5月24日 · #"the factors of + 12 which sum to + 13 are + 12 and + 1"# #x^2+13x+12=(x+12)(x+1)# Answer link. Jacobi J.

2015年12月15日 · Here, a = 2, b = 17 and c = 26. x = (-b +- sqrt(b^2 - 4ac))/(2a) = (-17 +- sqrt(17^2 - 4*2*26))/(4) " "= (-17 +- 9)/4 Thus, your second and your third roots are x = -2 and x = - 13/2 ===== 3) Finding positive intervals of the polynomial Now that you have the three roots, you know that the function intercepts the x axis three times, at -13/2, -2 ...

2015年5月6日 · x=+-1/2, +-1/3 Multiply by x^4 to give 36x^4-13x^2+1 Solve using the quadratic formula for x^2 x^2=(13 ...

2018年3月24日 · x=3+sqrt22 x=3-sqrt22 Given - x^2-6x=13 x^2-6x+9=13+9 (x-3)^2=22 x-3=+-sqrt22 x=+-sqrt22 +3 x=3+sqrt22 x=3-sqrt22

2016年7月4日 · #= x [x^2 + 13x + 42]# Now getting the factors of 42 and seeing if the sum of its factors equals to 13 ( middle value). By getting its factors ( #7*6# = 42) we have come to know that 7 + 6 equals to 13.

2018年7月17日 · Vertex form of equation is y=13( x+7/13)^2-20 3/13 y=13 x^2+14 x+24 or y=13 (x^2+14/13 x)+24 or y=13 {x^2+14/13 x+(7/13)^2}-49/13+24 or y=13( x+7/13)^2-263/13 or y=13 ...

2017年2月15日 · +-2 i and +-3 i x^4 + 13 x^2 + 36=0 assuming y = x^2, (x^2)^2 + 13 x^2 + 6 =y^2+13y+36=0 using y = (-b +- sqrt(b^2-4ac))/(2a), where a=1, b=13 and c=36 y = (-13+-sqrt ...

2015年12月12日 · (x-5)(x-8) There are many ways to factor. One method I like to use is the diamond method when you try to find the two numbers that add up to b and multiply to ac. y=ax^2+bx+c So you want to find two numbers that add up to -13 and multiply to 40. You can find the factors of 40 and find the pair that adds up to -13. -8 and -5 multiply to 40 and add up to …

2018年5月28日 · #x(x^2+color(red)(2x-15x)-30)# Notice, the red terms are the same as #-13x#, so I didn't change the value of this expression. #x(color(purple)(x^2+2x)color(lime)(-15x-30))# I can factor an #x# out of the purple term, and a #-15# out of the green term. Doing this, we get. #x(color(purple)(x(x+2))color(lime)(-15(x+2)))#

2017年5月27日 · y = -13(x+1/26)^2-987/52 is vertex form This gives the vertex as (-1/26, -18 51/52) The equation of a parabola can be written as: y = ax^2 +bx+c" " or in vertex form: " "y = a(x+b)^2 +c We have " "y = -13x^2-x-19 To change an equation into vertex form: Step 1. Make 1x^2. Divide out a, the coefficient of x^2 y = -13(x^2+x/13+19/13) Step 2.