Starting at the origin of your graph (where the x-axis crosses the y-axis), go to the right 2 squares (x=2) then up 1 square (y=1) and mark your first point. For the second point, again, start at the origin and go right 5 squares (x=5) and then up 4 squares (y=4) and mark your second point. Using a straight-edge, draw a line joining these two ...

Now get rid of the -1 on the left side by adding +1 to both sides and you have the answer of:.. You could also have begun the problem by multiplying out the left side ... multiplying y times (x-1). If you do that, the equation becomes:.. Next get rid of the -y term on the left side by adding +y to both sides. The result is:.. Now get rid of the ...

2023年6月30日 · Find an answer to your question 1 If y = x^1/x, then find dy dx at x = 1.

2022年2月17日 · The area of the region enclosed by the curves y = √(x + 1) and y = x + 1 is 1/6 square units. As per the question given, To find the area of the region enclosed by the curves y = √(x + 1) and y = x + 1, we need to find the points of intersection between the two curves and integrate the difference between them over the interval where they ...

2017年5月3日 · An equation consisting of two variables x and y. (x/y) + (y/x) = -1. To Find: The value of x³-y³. Solution: The given problem can be solved using the formula of a³ - b³. 1. The given equation is, => (x/y) + (y/x) = -1, 2. The above equation can also be written as, => (x * x + y * y)/xy = -1, (Transfer the term xy to the Right Hand side).

2018年3月16日 · y=(x-1)^2-2 (Graph below) y=x^2-2x-1 Since this does not factor, you can put this into a more graph-friendly equation by completing the square. y=x^2-2x-1 y=(x^2-2x+1)-1-1 y=(x-1)^2-2 The graph of this is a parabola with a vertex at (1,-2) and a "slope" of 1. graph{(x-1)^2-2 [-10, 10, -5, 5]}

You can graph the equation by assigning various values for x and computing the corresponding values of y. Do this for 3 or more convenient values of x and plot the resulting (x, y) points. For example:. When x = 0 then y = 0 + 1 = 1. This tells you that the (x, y) point (0, 1) is on the graph. Plot it.. When x = 5 then y = 5 + 1 = 6. .

2015年7月17日 · Solve y < x - 1 First, graph the Line y = x - 1 by its intercepts. Make x = 0 --> y = -1. Make y = 0 --> x = 1. The solution set of the inequality is the area below this Line. Color or shade it. That is the answer.

2017年10月27日 · The y-intercept is the value of #y# when #x=0# (that is, on the Y-axis, since for all values on the Y-axis, #x=0#) Substituting #0# for #x# in the given equation: #color(white)("XXX")y=(-0-1)(0+7)=-7#

2015年8月7日 · How do I graph the rational function #y=(x+2)/(x^2+1)# on a graphing calculator? What is the inverse function for #f(x) = x/(x-2)#? How do you graph #y=-5/x# using asymptotes, intercepts, end behavior?