2016年7月13日 · The domain is (-infty, infty) and the range is [-1,1]. This is a fun problem because we are presented with a modified version of the cos(x) function, but as we will see, it …

2014年8月6日 · We will need to employ the chain rule. The chain rule states: d/dx[f(g(x))] = d/(d[g(x)])[f(x)] * d/dx[g(x)] In other words, just treat x^2 like a whole variable, differentiate the …

2014年10月21日 · First, the graph of y=cos(x-pi/2) will have some characteristics of the regular cosine function. I also use a general form for trig functions: y = a cos(b ( x - c)) + d where |a| = …

2018年2月21日 · Shift points on the graph of y=cos(x) to the left by pi/2 units, plot a full period, and plot further using the fact that cosine is periodic and reflected over the y-axis if necessary. …

2015年6月6日 · How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with …

(dy)/(dx)=-sin(cos(cos(x)))sin(cosx)sin(x) In order to differentiate a function of a function, say y, =f(g(x)), where we have to find (dy)/(dx), we need to do (a) substitute u=g(x), which gives us …

2015年8月17日 · Always think of your chain, product and quotient rules when differentiating. #y cos x = 1 + sin (xy)# Diff wrt #x#:

2016年9月2日 · See explanation below graph{cos(pi*x) [-5, 5, -2, 2]} Graph of function y=f(x), by definition, is a set of all points (A,B) on the coordinate plane that satisfy the equation B=f(A). …

2017年10月6日 · Domain: {x in RR : -1<=x<=1} Range: {x in RR : -oo<= y < e^pi} f(x) = cos(e^x) or y=cos(e^x) We need to make x the subject of y=cos(e^x) cos^-1(y) = cos^-1(cos(e^x ...

2017年5月15日 · y=cosx+pi As y=cos^(-1)(x-pi) x-pi=cosy or x=cosy+pi Hence, inverse function of y=cos^(-1)(x-pi) is y=cosx+pi