Rewrite x4 x 4 as (x2)2 (x 2) 2. Rewrite 16 16 as 42 4 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 - b 2 = (a + b) (a - b) where a = x2 a = x 2 and b = 4 b = 4. Simplify. Tap for more steps...

Rewrite x4 x 4 as (x2)2 (x 2) 2. Rewrite 16 16 as 42 4 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 - b 2 = (a + b) (a - b) where a = x2 a = x 2 and b = 4 b = 4. Simplify. Tap for more steps...

Rewrite x^{4}-16 as \left(x^{2}\right)^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right). \left(x-2\right)\left(x+2\right)

Rewrite x4 x 4 as (x2)2 (x 2) 2. Rewrite 16 16 as 42 4 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 - b 2 = (a + b) (a - b) where a = x2 a = x 2 and b = 4 b = 4. Simplify. Tap for more steps...

x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)

2x4=16 Two solutions were found : x = ± ∜8 = ± 1.6818 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ... How do you factor \displaystyle{9}{x}^{{{4}}}-{16} ?

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Here we will solve the 4th-degree polynomial equation x^4=16 by factoring. We will use the difference of two squares factoring formula twice, along with complex numbers! I will also show...

$\Rightarrow {x^4} - 16 = ({x^2} + 4)(x + 2)(x - 2)$ This is the required solution. Additional Information: Know the difference between the squares and square root and apply the concepts accordingly.

Feb 13, 2016 · I was following a calculus tutorial that factored the equation $x^4-16$ into $(x^2 +4) (x+2)(x-2)$. Why is the factorization of $x^4-16 = (x^2 + 4)(x+2)(x-2)$ rather than $(x^2 - 4)(x^2 +4)$?