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Rewrite x^ {4}-16 as \left (x^ {2}\right)^ {2}-4^ {2}. The difference of squares can be factored using the rule: a^ {2}-b^ {2}=\left (a-b\right)\left (a+b\right).

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2x4=16 Two solutions were found : x = ± ∜8 = ± 1.6818 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

Reescribe x4 x 4 como (x2)2 (x 2) 2. Reescribe 16 16 como 42 4 2. Dado que ambos términos son cuadrados perfectos, factoriza con la fórmula de la diferencia de cuadrados, a2 −b2 = (a+b)(a−b) a 2 - b 2 = (a + b) (a - b), donde a = x2 a = x 2 y b …

Here we will solve the 4th-degree polynomial equation x^4=16 by factoring. We will use the difference of two squares factoring formula twice, along with complex numbers! I will also show...

How do you factor $ {x^4} - 16$?. Ans: Hint: Factorization of any polynomials can be written as the product of its factors having the degree less than or equal to the original polynomial. Here we will use the identity for the difference of two squares...

\(x^4-16\) Solution 1 \( \text{Write } x^{4} \text{ and } 16 \text{ in perfect square form.}\) \(x^{4} = {(x^{2})}^2 , 16 = {(4)}^{2} \) 2 \(\text{Rewrite } x^{4} - 16 \text{ as the difference of squares.}\)