2015年9月3日 · The reason there are two different ways to multiply vectors is to deal with different physical situations, so the dot product can be used for work, which is a scalar, F.D, and the …

2023年2月11日 · v2 = v ⋅ v - where ⋅ indicates the dot product. The result of the dot product is a scalar, not a vector; it doesn't have a direction. Example for your vector: u = 0i − 4j + 0k , …

2012年8月2日 · 1) Scalar multipication involves a scalar and a vector so there cannot be a "square". 2) The dot product gives a scalar result: <v1, v2, v3>.<u1, u2, u3>= v1u1+ v2u2+ …

2014年12月20日 · The dot-product multiplication is "component-wise," i.e., product of $x$-coords, plus product of $y$-coords. So the geometric interpretation is: the square of the length of the …

2019年8月5日 · The square of a vector is defined as follows: $$ A^2 := \mathbf{A}\cdot \mathbf{A} $$ However, with this definition then $\sqrt{\mathbf{A}\cdot \mathbf{A}} = A \neq \mathbf{A}$. …

2019年3月13日 · Specifically, the square of the norm of a vector v is equal to the inner product (or dot product) of v with itself. The inner product of two vectors is a scalar, regardless of if the …

2006年3月21日 · You can't "square" a vector, because there's no distinct "multiply" operation defined for vectors. The dot product is a generalization of multiplication to vectors, and you …

2013年9月26日 · [itex]\sqrt{a^2+b^2}[/itex] is the magnitude of [itex]\vec{a}±\vec{b} [/itex],where [itex]\vec{a}[/itex] and [itex]\vec{b}[/itex] are orthogonal (perpendicular) vectors. Sep 27, 2013 #6

2012年10月31日 · I have to calculate a square of vector which should results a scalar value. i.e) A=(B-C)^2 B and C are vectors and I need A as a scalar. How can I implement this in matlab??

What does squaring a vector mean? The quantity that represents the magnitude, as well as the direction of other quantities, are known as vector quantities. The dot product of a vector with …