2005年10月17日 · Use values of x like: pi, 2pi, 3pi, ... until you get a change in the sign of f(x). That means that the curve, f(x), has crossed the x-axis, and therefore has been, at some point, equal to zero between the two x-values that gave the change of sign. Take half-way between the two x-values as your first approximation, x 0.

2018年11月7日 · What I would do is multiply the original equation by \(2e^x\) so that we have: \(\displaystyle e^{2x}+1=6e^x\) ...

2010年4月24日 · x = 0 , x = 0, pi, 2pi Why is it when I graph the equation sin3x - sinx = 0 on my calculator, it comes with 7 solutions when i only have 3? The problem is that the use of your double angle was incorrect but the idea of solving the proble is correct the thing to do here is

2007年2月19日 · I wonder if you are not thinking of the "Lambert W function". W(x) is defined as the inverse of the function f(x)= xe x. If ln(x)+ x= 10, then, taking the exponential of each side, e ln(x)+ x = xe x = e 10. x= W(e 10). Of course, the only way to evaluate that is to do some kind of numerical approximation as others have said,

2019年3月18日 · You can't have a negative length, by definition, but you can have a negative displacement. In fact, in any case where you have a displacement along the x-axis, that displacement is positive or negative depending on the orientation of your x-axis. If by a negative time you mean ##t < t_0##, then that makes sense also.

2010年2月24日 · The equation is an exponential equation, since the variable you wish to solve for is in the exponent. You're part right, though -- the logarithm of a number is an exponent. More precisely, the logarithm, relative to some base, of a number a is the exponent on the base that produces that number.

2013年6月22日 · Note: if the rational root test fails, the equation has only nasty, irrational roots; for example, the slightly different equation x^3 - 2*x^2 - 1 = 0 has no rational roots. You can see that by showing that both x = +1 and x = -1 fail to solve the equation.

2015年4月1日 · it comes : x(t) =∫v(t)dt = 1/2 at^2 + vt + x(0), x(0) is the initial position assumed nill then x(0) =0

2008年3月6日 · 3.35*10^10 = (400)^(4-x) - (300)^(4-x) and you want to solve for x. Putting inside TI89, i get the answer x = -0.106072 But what if you do not have any calculator. I'm just wondering because i have a lot of numbers to solve and want to do it in software. I would have to import a lot of data, and each data is independent from each other.

2012年4月4日 · Hi every one, first post, so let me know if I'm not following any of the rules. I'm studying Calculus, looking at the rules for deriving the function a^x. The first step is to change a^x to e^(x(lna)). From there, it's easy to use the chain …