2017年9月18日 · How do I balance this equation? C4H8S+O2=CO2+H2O+SO3

2017年11月5日 · The reaction of sulfur trioxide with atmospheric water droplets results in sulfuric acid, a contributor to acid rain.According to the equation below, how many moles of sulfuric acid can you predict will be formed from 58.0 g of SO3 and an excess of water?

2017年3月5日 · Start with the skeleton equation: SO2 + O2 +H 2O → H 2SO4 Atoms on the left: 1 − S,5 − O,2 − H Atoms on the right: 1 − S,4 −O,2 − H To make the number of oxygen on the left to be even, add 2 molecules to H 2O and a 2 to the right. SO2 + O2 +2H 2O → 2H 2SO4 Atoms on the left: 1 − S,6 − O,4 − H Atoms on the right: 2 − S,8 …

2015年9月11日 · Sulfur trioxide reacts with water to form sulfuric acid, H2SO4, according to the balanced chemical equation SO3(g] +H2O(l] → H2SO4 (aq] The problem with this reaction is that it is extremely exothermic, meaning that it gives off very much heat. Actually, this reaction gives off so much heat that it can actually vaporize the sulfuric acid solution, producing very dangerous sulfuric acid vapor ...

2015年11月27日 · The Lewis acid is the electron pair acceptor; the Lewis base is the electron pair donor. SO_2(g) + H_2O(l) rarr H_2SO_3(aq) While it is not immediately obvious, it is clear that the sulfur species has accepted a lone pair from the water molecule; so sulfur dioxide is the Lewis acid in this example. A more old-fashioned treatment is to designate sulfur dioxide as the acid anhydride of sulfurous ...

2017年9月18日 · Al2O3(s) + 3H 2SO4 → Al2(SO4)3 +3H 2O(l) For each equiv of oxide we need to supply 2 equiv H +, i.e. 1 equiv H 2SO4.

2018年5月9日 · S8(s) +12O2(g) → 8SO3 To make this a little easier we could use fractional coefficients... 1 8 S8(s) + 3 2O2 → SO3(g) Industrially, this is performed by the contact process. Sulfur is burned in air... 1 8 S8(g) + O2(g) → SO2(g) And then this is further oxidized to SO3 by means of a vanadium pentoxide catalyst... SO2(g) + 1 2O2(g) V 2O5 −→ SO3(g) This must be a very dirty, nasty, and ...

2015年11月21日 · The bisulfite anion. As you know, the conjugate base of an acid is determined by looking at the compound that's left behind after the acid donates one of its acidic hydrogen atoms. The compound to which the acid donates a proton acts as a base. The conjugate base of the acid will be the compound that reforms the acid by accepting a proton. In this case, sulfurous acid has two protons to donate ...

2015年1月16日 · For H2O → H: +1, O: -2. Notice that Mn goes from +7 on the reactants' side, to +2 on the products side, which means it has been reduced, while S goes from +4 on the reactants' side, to +6 on the products' side - it has been oxidized.

How do you balance this redox reaction using the oxidation number method? HNO3 (aq) + H3AsO3 (aq) --> NO (g) + H3AsO4 (aq) + H2O (l)