2017年12月10日 · $\ce{SO2(g) + H2O(l) = H2SO3(aq)}$ What I tried: A Lewis acid is an electron pair acceptor. A Lewis base is an electron pair donor. The other problems of this type involved cations or anions, so I was able to identify the cation as the Lewis acid and the anion as the Lewis base. However, this question does not involve ions.

2017年3月5日 · 2SO_2 + O_2 + 2H_2O -> 2H_2SO_4 Start with the skeleton equation: SO_2 + O_2 + H_2O -> H_2SO_4 Atoms on the left: 1-S, 5-O, 2-H Atoms on the right: 1-S, 4-O, 2-H To make the number of oxygen on the left to be even, add 2 molecules to H_2O and a 2 to the right. SO_2 + O_2 + 2H_2O -> 2H_2SO_4 Atoms on the left: 1-S, 6-O, 4-H Atoms on the right: 2-S, 8-O, 4-H To make the number of S to be the ...

2015年8月16日 · Therefore we expect $\ce{SO2}$ to have the largest bond angle of the four molecules, and this is indeed the case. $\ce{H2O}$ and $\ce{NH3}$ are hydrides of the same period so we can use the first rule to determine that $\ce{H2O}$ has a smaller bond angle. Now we just have to decide whether $\ce{H2O}$ or $\ce{H2S}$ has a smaller bond angle.

2015年6月13日 · Upon adding $\ce{SO2}$ gas to water, it shows its acidic oxide character by hydrolyzing to sulfurous acid: $$\ce{SO2(g) + H2O(l) <=> H2SO3(aq)}$$ $\ce{H2SO3}$ is a weak diprotic acid in water, with the following acid dissociation equilibria:

2020年8月26日 · Majority of texts (at high school level) say that when $\ce{SO2}$ is dissolved in water sulphurous acid $\ce{H2SO3}$ is formed. However my text book states that it forms clathrate $\ce{SO2.6H2O}$ when dissolved in water, and can significantly exist as $\ce{H+ + HSO3-}$. I found similar finding on Wikipedia:

2014年8月9日 · The temperature is 810 °C. > There are four steps in this problem: Write the balanced chemical equation. Calculate the moles of sulfur. Calculate the moles of H₂S. Use the Ideal Gas Law to calculate the temperature. 1. Write the balanced chemical equation 2H₂S + SO₂ → 2H₂O + 3S 2. Calculate the moles of sulfur Moles of S = 3.2 g S × (1"mol S")/(32.06"g S") = 0.0998 mol S 3 ...

2014年7月13日 · Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid), unbalanced. If 3.0 L of H2S gas at 760 torr produced 4.8 g of sulfur, what is the the temperature in Celsius?

2016年1月7日 · Orthocresol already sufficiently pointed out, that half-reactions are a book-keeping tool for electrons. When talking about electrolysis there might be coincidental overlap between half-reactions and the overall mechanism, but as the wording is supposed to indicate, this is not necessarily true.

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2018年3月1日 · Since $\ce{SO2}$ is a strong reducing agent, it reduces $\ce{Mn}$ as denoted by the equation $$\ce{5SO2 + 2KMnO4 + 2H2O -> 2H2SO4 + 2MnSO4 + K2SO4}$$ Both the reactions are viable. Because of the formation of $ \ce{MnSO4}$ and the disappearance of $ \ce{KMnO4}$, decolorisation occurs.