
What is the compound Sn SO3 2? - Answers
2024年6月15日 · The compound Sn SO3 2 is Tin (IV) Sulphite. It can be produced easily in a chemistry lab, but has few if any commercial applications.
What is the chemical formula of stannic sulfite? - Answers
2024年5月28日 · The chemical formula of stannic sulfite is Sn(SO3)2. AnswerBot. ∙ 10mo ago. Copy. Add a Comment. Sn(SO3)2. Wiki User. ∙ 12y ago. Copy. Add a Comment. ... (SO3)3. What is the chemical formula ...
What is the chemical name for SO3 2-? - Answers
2024年5月24日 · The chemical name for SO3^2- is sulfite ion. AnswerBot. ∙ 10mo ago. Copy. Add a Comment. Sulfur trioxide. Wiki User. ∙ 14y ago. Copy. ... The chemical formula of stannic sulfite is Sn(SO3)2.
What is the oxidation state of each element in SO3 -2?
2024年6月15日 · What is the compound Sn SO3 2? The compound SnSO3 is tin(II) sulfite. The Roman numeral (II) indicates that tin is in the +2 oxidation state, while sulfite is a polyatomic ion with the formula SO3^2-.
What is the formula for oxyacid dervied from SO3 2-? - Answers
2024年5月28日 · The chemical formula of stannic sulfite is Sn(SO3)2. What is the chemical formula for sulfide ion? The chemical formula for sulfide ion is S^2-. It consists of one sulfur atom carrying a charge of -2.
Is tin III sulfate soluble in water? - Answers
2024年5月29日 · The answer is yes because sulfate is only soluble to any positive ion and tin (Sn) happened to to be a cation with a positive 4 charge so that makes Sn(SO3)4 soluble .
What is the chemical formula for tin (IV) sulfide? - Answers
2024年6月21日 · i think its Sn(SO3)4 What is the formula for Tin(IV) iodide? Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state.
What is the name of Sn ClO3 2? - Answers
2024年6月18日 · The correct formula for stannous chlorate is Sn(ClO3)2. It consists of one tin (Sn) atom bonded to two chlorate (ClO3) ions. Formula for Tin IV Chloride? The formula for Tin(IV) chloride is SnCl4.
Is SO2 plus O2---SO3 balanced - Answers
2024年6月17日 · S8 + 12O2 = 8SO3.Since there are 8 sulfur on the left, you must have 8 on the right, so 8SO3. Now you have 24 oxygen on the right, so you need 24 on the left. Multiplying O2 by 12 balances it.
How many Lewis resonance structures are there for the SO3 2 ion ...
2024年6月29日 · Study now. See answers (3) Best Answer