The Wolff–Kishner reduction is a reaction used in organic chemistry to convert carbonyl functionalities into methylene groups. [1][2] In the context of complex molecule synthesis, it is most frequently employed to remove a carbonyl group after it has served its synthetic purpose of activating an intermediate in a preceding step.

2025年2月25日 · Hydrazones can be further converted to the corresponding alkane by reaction with a base, usually KOH, and heat. Typically a high boiling point solvent, such as ethylene glycol, is used to provide the high temperatures needed for this reaction to occur.

2018年8月27日 · The Wolff Kishner reduction of ketones utilizes hydrazine (NH 2 NH 2) as the reducing agent in the presence of strong base (KOH) in a high-boiling protic solvent (ethylene glycol, HO-CH 2 CH 2 -OH, boiling point 197 °C). The driving force for the reaction is the conversion of hydrazine to nitrogen gas.

2024年9月30日 · A useful variant of the imine-forming reaction just discussed involves the treatment of an aldehyde or ketone with hydrazine, H 2 N–NH 2, in the presence of KOH. Called the Wolff–Kishner reaction, the process is a useful and general method for converting an aldehyde or ketone into an alkane, \(\ce{R2C=O→R2CH2}\).

Treatment of the new hydrazone molecule with a base (NaOH, KOH) in hot conditions (commonly referred to as ‘heat’ or ‘ Δ ’, will remove the NNH2 group and reduce the molecule down to an alkane

A useful variant of the imine-forming reaction just discussed involves the treatment of an aldehyde or ketone with hydrazine, H 2 N–NH 2, in the presence of KOH. Called the Wolff–Kishner reaction, the process is a useful and general method for converting an aldehyde or ketone into an alkane, R 2 C=O → R 2 CH 2 R 2 C=O → R 2 CH 2.

2020年6月10日 · koh-dmso体系是有名的强碱体系，因为oh-在非极性溶剂中碱性大大增强。knh2的碱性也非常强。且有nh3作为反应产物逸出体系的buff。 二者在有机溶剂中碱性相当，而且koh碱性可能更大，因为o的电负性比n大，且o周围原子排列没有n拥挤。

2009年6月9日 · naohやkohの共存下、アルデヒドやケトンをヒドラジンとエチレングリコール中加熱することで、炭化水素が得られる(黄鳴竜変法)。 ホーム ブログ

Question: NH2NH2, KOH . Draw "arrow pushing" mechanism for this reaction. Show transcribed image text. Here’s the best way to solve it. Solution.

\phantom{....}\ce{C = \underset{Hydrazine}{O + H2N - NH2} -> C = N - NH2 ->[glycol + KOH][180°C] CH2 + N2(g)}\\ \phantom{..}/\phantom{.........................}/\phantom{........................}/\phantom{.............}\\