Question 579546: The expression ln (2e^3x) is equal to? a. ln 2+3x b. ln(2+3x) c. ln 6x d. ln 2+3

2016年1月3日 · What are the first and second derivatives of #f(x)=ln(-2e^(-6x^3)+x^2) #? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer

2018年2月20日 · x=ln(2)/2 2 e^(2x)=4 e^(2x)=2 Put the natural log function around both sides: ln( e^(2x))=ln(2) Recall the exponential logarithm property which states that log( a^x)=xlog(a) and …

2016年9月25日 · (x+2)/x This can be significantly simplified first using logarithm rules. The first we will use is that log(AB)=log(A)+log(B), so: y=ln(x^2e^x)=ln(x^2)+ln(e^x) Since ln(x)=log_e(x) …

2015年4月28日 · Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases

2024年6月10日 · Try posting in the maths forum next time. ln(2e) = ln2 + lne (by log rules) = ln2 + 1 (as ln e 1 = e ln 1 ...

2016年10月30日 · (ln(x^2e^x))'=(2+x)/x (ln(x^2e^x))''=-2/x^2 The derivative of the given function is determined by using chain rule and applying some differential properties of the function lnx …

2017年2月5日 · y' = (2 + x)/x y'' = -2/x^2 This can be rewritten as y = lnx^2 + lne^x We know that y= lnx and y = e^x are inverses, such that lne = 1. Using the law lna^n = nlna, we can say that …

2016年12月4日 · How do you find the particular solution to #(dr)/(ds)=e^(r-2s)# that satisfies r(0)=0? Calculus Applications of Definite Integrals Solving Separable Differential Equations

2018年6月26日 · x^2 - x +c Use knowledge of logarithms log_a a^f(x) -= f(x) ln_a a -= f(x) Hence ln e^f(x) -= f(x) => int ln (e^(2x-1) ) dx = int (2x-1) dx Use the reverse power rule: = x^2 -x + c