2017年6月16日 · Iron cannot skip the #3d# orbitals and use #4p# orbitals. We know already that the #4p# orbitals are higher in energy than the #3d# orbitals, by virtue of the #4p# having a higher #l# than the #4s#, and the #4s# being at least CLOSE in energy to the #3d#.

2017年7月10日 · Well, from the diagram, the electron shells, using so-called "KLMN notation" (or X-ray notation), have the configuration 2, 8, 8, 1.

2016年1月13日 · (.5,0) To answer the question we need to find the equations of the diagonals KM and LN and combine them to find the point or intersection. The formula for the equation of the line is (y-y_0)=k(x-x0) where k=(Delta y)/(Delta x)=(y_1-y_0)/(x_1-x_0) Equation of the line 1 in which the diagonal KM lays: k_(KM)=(-4-4)/(1-0)=-8 (y-4)=-8x => y=-8x+4 Equation of line 2 in which …

2017年7月8日 · The KLMN electron configuration of Argon is 2, 8, 8 each number referring to the electrons in the shells or energy levels of the atom.

2016年5月24日 · It can be very confusing to think of it this way. Potassium has access to its 1s, 2s, 2p, 3s, 3p, and 4s orbitals.

2018年2月22日 · Rotated about origin by (3pi)/2 clockwise. L’(-4,2), M’(-3,3) Given : K (1,3), L (2,4), M(3,3), K’ (-3,1) K(1,3) -> K’(-3,1) changed from I quadrant to II ...

2018年3月3日 · Please see below. . If (x_1,y_1) and (x_2,y_2) are coordinates of the end points of a line segment the coordinates of the midpoint can be found using the following formulas: ((x_1+x_2)/2,(y_1+y_2)/2) In order to prove that RS is the midsegment of the trapezoid, we need to prove that R is the midpoint of KN, and S is the midpoint of LM and RS is parallel to the bases.

2016年6月21日 · The full electron configuration for nitrogen is "1s"^ 2"2s"^2"2p"^3. The noble gas shorthand electron configuration is ["He"]"2s"^2"2p"^3". The atomic number of nitrogen is 7. This is the number of protons in the nuclei of nitrogen atoms. A neutral atom has the same number of electrons as protons. So the electron configuration will include 7 electrons placed into the …

MN = sqrt5 The length of MN is: MN = sqrt((x_n-x_m)^2+(y_n+y_m)^2) MN = sqrt((-4--2)^2+(-4--5)^2) MN = sqrt((-2)^2+(1)^2) MN=sqrt5

2014年1月25日 · Copper is in the ninth column of the transition metals in the d block of the fourth energy level of the periodic table. This would make the electron configuration for copper, 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^9 or in noble gas configuration [Ar] 4s^2 3d^9. However, because the 3d orbital is so much larger then the 4s orbital and the 3d orbital only needs one more …