Multiply both sides of the equation by \left(j+3\right)\left(j+10\right), the least common multiple of j+10,j+3. j^{2}-5j-24=\left(j+10\right)\left(j-1\right) Use the distributive property to multiply j+3 by j-8 and combine like terms.

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2j^{2}-j-10=2\times \frac{2j-5}{2}\left(j+2\right) Subtract \frac{5}{2} from j by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

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#include <iostream> using namespace std; int main(){ int i, j; for ( i = 5, j = 10 ; i + j < 20; i++, j++ ) { cout << "i + j = " << (i + j) << '\n'; } } /* Output: i + j = 15 i + j = 17 i + j = 19 */ loop-expression can be incremented or decremented, or modified in other ways.

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2022年4月22日 · I have added a line that should exit the J loop when J = 10. Hope it helps. Set myGrid = session.findById("wnd[0]/usr/cntlGRID1/shellcont/shell/shellcont[1]/shell")

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Game Bar is built into Windows so you can capture videos and screenshots while playing PC games. While you're playing a game, press the Windows logo key + G on your keyboard to open Game Bar.; Select Record from now (the circle) to start a clip, then Stop recording (the square) to end it.; Select Take screenshot (the camera icon) to take a picture of what’s happening in the …

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