Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients. a Sn + b HNO3 = c SnO2 + d NO2 + f H2O. Create an equation for each element (Sn, H, N, O) where each term represents the number of atoms of the element in each reactant or product.

现在，两边都有 4 个 H 原子和 2 个 O 原子。 方程式平衡。 该方法使用代数方程来找到正确的系数。 每个分子的系数由一个变量（如x、y、z）表示，并根据每种原子的数量建立一系列方程。 最适合：更复杂且不易通过检查平衡的方程。 过程：为每个系数分配变量，为每个元素编写方程，然后求解方程组以找到变量的值。 将其中一个系数赋值为 1 并求解该方程组。 调整系数以确保它们都是整数。 b = 3.5 因此我们需要将所有系数乘以 2 以获得具有整数系数的平衡方程：

Sn(s) + 4 HNO 3 (aq) = SnO 2 (s) + 4 NO 2 (g) + 2 H 2 O(l) Direct link to this balanced equation: Please tell about this free chemistry software to your friends!

1 Sn + 1 HNO 3 (conc) = 1 Sn(NO 3) + 1 NO 2 + 1 H 2 O For each element, we check if the number of atoms is balanced on both sides of the equation. Sn is balanced: 1 atom in reagents and 1 atom in products. H is not balanced: 1 atom in reagents and 2 atoms in products. In order to balance H on both sides we: Multiply coefficient for HNO 3 (conc ...

Sn is a reducing agent (i.e. it lost electrons) and HNO 3 is a oxidizing agent (i.e. it gained electrons). Balance Sn + HNO3 = SnO2 + NO2 + H2O and find the reducing and oxidizing agents.

In the oxidation number change method the underlying principle is that the gain in the oxidation number (number of electrons) in one reactant must be equal to the loss in the oxidation number of the other reactant. Step 1. Write down the unbalanced equation ('skeleton equation') of the chemical reaction. All reactants and products must be known.

已求解并配平的化学方程式 sn + 4 hno3 → h2o + h2sno3 + 4 no2 具有完整的产物. 请求补充完整产物并配平方程. 如果未启用JavaScript，某些功能可能无法正常运行。

¡Balancea la ecuación o reacción química Sn + HNO3 = SnO2 + NO2 + H2O utilizando la calculadora!

Sn + 4 HNO3 → SnO2 + 4 NO2 + 2 H2O - Balanced equation | Chemical Equations online! This is an oxidation-reduction (redox) reaction: Sn is a reducing agent, HNO3 is an oxidizing agent. Appearance: White crystalline powder ; Gray to almost …

2018年10月23日 · It is a common belief that tin dissolves in dilute nitric acid to produce tin (II) nitrate. The reactions are addressed in a previous answer of mine. However, employing a more hot and concentrated nitric acid yields an unstable compound called hydrated stannic oxide also known as β-stannic acid.