SOLUTION: When does cos(x) = 0? - Algebra Homework Help
When does cos(x) = 0? From the "unit circle" cos(x)=0 when In terms of degrees: 90 and 270 degrees
SOLUTION: For sin2x+cosx=0, use a double-angle or half-angle …
For sin2x+cosx=0, use a double-angle or half-angle formula to simplify the equation and then find all solutions of the equation in the interval [0,2π). *** sin(2x)+cosx=0 2sinxcosx+cosx=0 …
How do you solve #2sin^2x = 1 + cosx# for #0° <= x <= 180°
2018年3月20日 · Now here's the actual problem. The strategy is to get everything in terms of #cosx#, then factor it like a quadratic. Here's what that looks like: #2sin^2x=1+cosx# #2(1 …
Evaluate the remaining trigonometric functions? CSC x is ... - Socratic
2018年4月16日 · sinx=0, cosx=-1, tanx=0, cotx=undefined secx= -1 If cosecant is undefined, that means it is over 0. Remember that cosecant is hypotenuse over opposite side (reciprocal of …
SOLUTION: solve 2sinx+cosx=0 - Algebra Homework Help
Click here to see ALL problems on Trigonometry-basics; Question 775657: solve 2sinx+cosx=0 Answer by Tatiana_Stebko(1539) (Show Source):
SOLUTION: If tanx=-1/3 ; cosx>0 then sin2x= cos2x= tan2x=
If tanx=-1/3 ; cosx>0 --Since tan is negative and cos is positive, x is in the 4th quadrant.----- tan = y ...
SOLUTION: how do you solve sin(x/2)+cosx=0 with a restriction of …
cosx=1 x=0 Answer by Barbazzo(2) (Show Source): You can put this solution on YOUR website! Transform Cos ...
SOLUTION: \Find the general solution: cosx*tanx -cosx=0 Thanks!
You can put this solution on YOUR website! Find the general solution:[0,π/2] cosx*tanx -cosx=0 cosx(tanx-1)=0 ...
How do you solve #1+cosx-2sin^2x=0# and find all solutions
2018年6月11日 · See below Given 1+cosx-2sin^2x=0 we can do some changes based on trigonometric identities like 1+cosx-2(1 ...
How do you solve #cos x = sin 2x#, within the interval [0,2pi)?
2016年4月9日 · hence: cosx = 2sinxcosx. and 2sinxcosx - cosx = 0. take out the common factor cosx. cosx( 2sinx - 1 ) = 0. We now have : cosx = 0 or 2sinx - 1 = 0 → # sinx = 1/2 # solve : …