From the derivative of \\sin(x), \\cos(x) and \\tan(x) can be determined. \\cos(x) can be found by using the chain rule and the identity \\cos(x)=\\sin(x+90). \\tan(x ...

2018年4月6日 · #sin^2x-cos^2x# The key realization is that the original expression in question was in a difference of squares pattern. If you have a #(a-b)(a+b)# pattern, you can always use the difference of squares identity to quickly simplify it.

2016年8月13日 · Here we would use the quotient rule of differentiation. We have the following rule, d/dx(u/v) = (v(du)/dx - u(dv)/dx)/v^2 Here, u(x) = x and v(x) = Cos x Putting u(x) = x and v(x) = Cos x Let, y = x/(Cos x) = u/v Thus, (dy)/dx = d/dx(u/v) = (v(du)/dx - u(dv)/dx)/v^2 implies (dy)/dx = (Cos x + x*Sinx)/Cos ^2x Where d/dx (x) = 1 and d/dx (Cos x) = - Sin x which are standard derivatives obtained ...

2016年6月2日 · There is a group of Trig Identities that contain: #cos(A-B)=cos(A)cos(B)+sin(A)sin(B)# For your question this translates to:

2016年1月26日 · csc x We start from the given sin x+cotx cos x sin x+(cos x/sin x)*cos x sin x*(sin x/sin x)+(cos x cos x)/sin x because sin x/sin x=1, we can always use it in any part of the equation or expression. fractions having the same denominator can be combined. it follows sin ^2 x/sin x+cos ^2 x/sin x (sin^2 x+cos^2 x)/sin x but sin^2 x+cos^2 x=1 therefore 1/sin x simplifies to csc x Have a nice day ...

2018年2月25日 · The first step to this problem is to use a Pythagorean Identity: #cos^2x=1-sin^2x# But we only want to replace one of the #cos^2x# so we can rewrite the identity like this for clarity:

2016年3月24日 · pi/3 and (4pi)/3 Apply the trig identity: cos a + cos b = 2cos ((a + b)/2).cos ((a - b)/2) cos (x + pi/3) + cos x = 2cos (x + pi/6)cos (pi/6) = 0 Trig table --> cos ...

(dy)/(dx)=-sin(cos(cos(x)))sin(cosx)sin(x) In order to differentiate a function of a function, say y, =f(g(x)), where we have to find (dy)/(dx), we need to do (a) substitute u=g(x), which gives us y=f(u).

2015年7月22日 · The values of x where this is not true are those values of x which make either cos(x)=0 or sin(x)=0. One of these will happen at each value of x that is an integer multiple of pi/2 radians (90 degrees). Hence, tan(x)cos(x)csc(x)=1 for …

2018年4月24日 · See below: cosx-cos^3x=cosxsin^2x cosx(1-cos^2x)=cosxsin^2x (1-cos^2x)=sin^2x "Remember the identity "color(red)( sin^2x+cos^2x=1=>1-cos^2=sin^2x :.sin^2x=sin^2x