2025年2月1日 · Let us assume we dissolve $\pu{1280 g}$ of $\ce{CaCl_2}$ in $\pu{1 L}$ of water at the ambient temperature of $\pu{40 ^\circ C}$. According to this Wikipedia table, this is the saturation point of the solution. Since the reaction is exothermic it will emit heat.

2016年10月1日 · Doing a first year chem class. Just read through the molecular naming of compounds and now I'm confused as to why $\\ce{CaCl2}$ is called calcium chloride and not calcium dichloride?

2013年5月17日 · The answer is simple. One of the unique properties of any salt is that it completely breaks down when dissolved in water. By that I mean each of the atoms clings to water molecules, preventing them from using their natural ionic bonds to each other. For every NaCl molecule, you can occupy 2 water molecules.

2019年5月10日 · 2 $\begingroup$ @AdnanAL-Amleh Yes. 0.025 M for $[OH-] $ is a low estimate, it is probably higher because $\ce{Ca(OH)+}$ can dissociate too. $\endgroup$ – permeakra

Edited: Salt with more total ions is more effective. $\ce{CaCl_{2}}$ is the one of the most available salt with 3 total ions. $\ce{MgCl_{2}}$ is another option. Some crude $\ce{NaCl}$ produced from sea water directly contain $\ce{Ca}$ and $\ce{Mg}$ salt and can be used to melt ice.

2014年4月12日 · Of the molar conductance value of $\ce{Ca^2+}$ and $\ce{Cl^-}$ at infinite dilution are respectively $118.88\times10^{-4}$ and $77.33\times10^{-4}$ then that of $\ce{CaCl2}$ is (all have same unit) So what I did was I added the molar conductivity of $\ce{Ca^2+}$ and added $2\times$ molar conductivity of $\ce{Cl^-}$.

2015年5月19日 · I have an aqueous solution of either $\ce{MgCl2}$ or $\ce{CaCl2}$ in solution with $\ce{K2SO4}$. There is a white precipitate that forms on the bottom that does not dissolve when $\ce{HCl}$ is added

2015年4月2日 · I have calcium chloride in the form of small (1-2 mm) round white pellets, originally bought at a home-brew shop. The packaging gives no indication what hydrate it is. Since each water molecule add...

2017年10月28日 · Yes, I think that lower alcohols cannot be dried using $\ce{CaCl2}$ as they form stable complexes with it but higher alcohols can be dried using $\ce{CaCl2}$ as they form unstable complexes while water forms stable complex.

2013年6月27日 · 1.) heat the wire before inserting it into the mixture of molten $\ce{CaCl_2}$. 2.) heat the $\ce{CaCl_2}$ well above its melting point. If you are determined to make Calcium metal it might be worth electrolysing an aqueous solution of $\ce{CaCl_2}$ to evolve the $\ce{Cl2(g)}$ (do this responsibly outside/in fume hood of course as $\ce{Cl2(g ...