WBJEE 2011: Two aromatic compounds having formula C7H8O which are easily identifiable by FeCl3 solution test (violet colouration) are (A) o-cresol and

An organic compound with molecular formula, C7H8O , dissolves in NaOH and gives characteristics colour with neutral FeCl3 . On treatment with bromine-water, it gives a tribromo derivative, C7H5OHBr3. The compound is

An organic compound (X) of the formula C7H8O is soluble in NaOH but not in NaHCO3 . It gives colour with alcoholic FeCl3 . On treatment with bromine water it gives tribromo product. The compound 'A' is

An organic compound (X) with molecular formula, C7H8O is insoluble in aqueous NaHCO3 but dissolves in NaOH. When treated with bromine water (X) rapidly gives (Y),C7H5OBr3 . The compounds (X) and (Y) respectively, are

NTA Abhyas 2020: The total number of isomers for the aromatic compound having molecular formula C7H8O is (A) 2 (B) 3 (C) 4 (D) 5. Check Answer and Sol

An aromatic compound A ( C 7 H 8 O ) gives following tests with the given reagents.

A compound (A) of molecular formula C7H8O is insoluble in water and dilute sodium bicarbonate but dissolves in dilute aqueous sodium hydroxide and gives a characteristic colour with aqueous FeCl3. On treatment with bromine water, it readily gives a precipitate of C7H5OBr3. Write down the structure of the compound (A).

NTA Abhyas 2020: An organic compound (X), C7H8O , is insoluble in both NaHCO3 and NaOH. On treatment with bromine-water (X) rapidly forms compound of

Total number of isomers of C7H8O containing benzene ring is (A) 3 (B) 4 (C) 5 (D) 6. Check Answer and Solution for above Chemistry question - Tardigrade

BHU 2001: The number of isomers shown by the compound with molecular formula C7H8O is: (A) 2 (B) 3 (C) 5 (D) 7. Check Answer and Solution for above Ch