2015年6月7日 · The radius of those circles is in average b, but it can be as much as b+a (outer ridge of the torus) and as little as b-a (inner ridge of the torus). For any s, the radius of the circle will be b+cos s, if we choose s so that s=0 corresponds to the position where the radius is …

2015年9月16日 · I was trying to calculate the surface area of a torus, whose tube radius is r, and distance from "singularity" to the center of the torus tube is R. Here's what I've tried to do (The reason I think I'm wrong is because of wolfram alpha torus page). I should note that the same methode did yield the right volume.

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2015年6月29日 · I have been trying to find the surface area of the torus generated by the rotation of $(x-R)^2 + y^2 = r^2$ about the y axis. I tried to use the equation: $$\int_a^b2\pi y\sqrt{1+\left(\frac {dy}{dx}\right)^2}dx$$ I know that the derivative of the equation is $$\frac {dy}{dx}= \frac {-(x+R)}{\sqrt{r^2-(x+R)^2}}$$

For a calculus question I need to parameterise the surface of the torus generated by rotating the circle ...

surface area of torus of revolution. Ask Question Asked 13 years, 4 months ago. Modified 13 years, 4 ...

2018年12月11日 · So the surface-mass/volume distribution is negligibly higher away from the centre of the torus, offsetting the centre of mass/volume of the element negligibly away from the centre of the torus. In most practical applications, this difference is too small to matter, and we can define the average radius of the torus either as the distance of the ...

2022年12月15日 · I have an idea of doing an optimization problem with a torus. Either to minimise the surface area with a fixed volume, or to maximise the volume with a fixed surface area. But I'm not sure if such maximum or minimum exists since r can shrink infinitely. Could this idea work, or if not, is there any similar things about the Torus that I can do?

surface area of a Torus using differential forms, Ask Question Asked 10 years, 11 months ago.

For a torus with radius 5, with the inner circle 10 units away from the z axis but I was wondering how ...