Train for the AMC 12 with outstanding students from around the world in our AMC 12 Problem Series online class. AMC 12 problems and solutions.

2021 AMC 12 A problems and solutions. The test will be held on Thursday, February , . The problems on this page are copyrighted by the Mathematical Association of America 's American Mathematics Competitions.

AMC 12 数学竞赛从2000年至今历年的真题及答案。 从2002年开始分A赛和B赛，自2021年秋季开始，改为于每年11月初和中旬举办。

2024 AMC 12A Problems Problem 1 What is the value of Problem 2 A model used to estimate the time it will take to hike to the top of the mountain on a trail is of the form where and are constants, is the time in minutes, is the length of the trail in miles, and is the altitude gain in feet. The

2024年11月11日 · 以上仅展示2023年AMC 12A部分真题，完整版扫描文末二维码即可免费领取，还有更多历年真题+视频解析~ 还有完整版中英双语真题试卷+全英版pdf真题供您选择，扫码即可免费领取完整版： 扫码添加顾问老师免费领取. 2023年AMC12 A卷最新真题+答案+导师视频解析

2022年AMC10/12A卷考试已结束，犀牛教育AMC竞赛教研团队也在第一时间对2022年AMC10A卷进行解析。 这次的题目难度感觉和去年是差不多的，其中 简单部分问题要更好做 一些，但问题的提法也与以往有区别，部分题目在阅读方面设置了许多障碍，容易让学生感觉能做出来但是耗费很多时间。 2022年 AMC12A卷 真题答案. 1-5：DEBBC; 6-10：DDAAE; 11-15：EBACD; 16-20：DAADB; 21-25：EADEE; 本次考试难度有哪些变化呢？ 变化一：增加 不定方程 的特殊形 …

2024 AMC 12A Printable versions: Wiki • AoPS Resources • PDF: Instructions. This is a 25-question, multiple choice test. Each question is followed by answers marked A, B, C, D and E. Only one of these is correct.

2021年AMC 12A（11月份）真题： Problem 1. What is the value of ? Problem 2. Menkara has a index card. If she shortens the length of one side of this card by inch, the card would have area square inches. What would the area of the card be in square inches if instead she shortens the length of the other side by inch? Problem 3

2020 AMC 12A 真题及答案. 首发文字版，查看2020 amc12A 晋级2020 AIME cutoff 分数线. 参考答案见文末（仅供参考） Problem 1. Carlos took of a whole pie. Maria took one third of the remainder. What portion of the whole pie was left? Problem 2. The acronym AMC is shown in the rectangular grid below with grid lines spaced ...

2022 AMC 12A problems and solutions. The test was held on Thursday, November 10, 2022. The problems on this page are copyrighted by the Mathematical Association of America 's American Mathematics Competitions.