
How do you simplify first and then solve −(1 + 7x) − 6(−7 − x)
2014年9月28日 · -( 1 + 7x) -6 (-7-x) = 36 it can be written as ; -1 ( 1 + 7x) -6 ( 7-x) =36 -1*1 + (-1) 7x -6*7 -6*(-x)= 36 -1 + -7x -42 + 6x =36 -1 -42 -7x +6x = 36 -43-x = 36 ...
Plz help Solve for x? - Socratic
2018年1月19日 · x = 36/(4(3(dy/dx)+2)^2) + 7/4 I am assuming thaty you want to solve for x in terms of dy/dx rather than in terms of dy and dx. dy/dx=2/sqrt(4x-7)-2/3 Replace dy/dx by D to …
How do you solve -( 2 + 7x ) - 6( - 7- x ) = 36? | Socratic
2016年9月23日 · x=4 Remove the brackets first. Be Careful with the negative signs -( 2 + 7x ) - 6( - 7- x ) = 36 -2-7x +42+6x = 36" "larr collect like terms and re-arrange, 40-36 = x" "larr move …
How do you calculate the left and right Riemann sum for the given ...
2017年2月10日 · See below. Cut the interval [6,8] into n=2 equal subintervals. The width (length) of each subinterval will be Delta x = (b-a)/n = (8-6)/2 = 1 The subintervals are [6,7] and [7,8] …
Solutions Using the Discriminant - Algebra - Socratic
#x^2-x-2=0# Where: #a=1#, #b=-1# and #c=-2# So: #Delta=b^2-4ac=1+4*2=9>0#, giving #2# real distinct solutions. The discriminant can also come in handy when attempting to factorize …
What is the equation of the normal line of f(x)=sqrt(3x^2+2x
2015年11月10日 · y=-4/7x+36/7 f'(x)=frac{d}{dx}((3x^2+2x)^{1/2}) =1/2(3x^2+2x)^{-1/2}(6x+2) The tangent line should pass through the point (2, f(2)), and have a gradient of -1/{f'(2 ...
Suppose T_4(x) = 7-3(x-2)+7(x-2)^2-6(x-2)^3+8(x-2)^4 is the
2017年4月19日 · Suppose #T_4(x) = 7-3(x-2)+7(x-2)^2-6(x-2)^3+8(x-2)^4# is the 4th-degree Taylor polynomial centered at #x=2# for some function f, what is the value of #f^((3))(2)#? …
If y varies directly as x^3 and y=36 when x=7, find y if x=4?
2018年5月1日 · If y varies directly as x^3 and y=36 when x=7, find y if x=4? (Round answer to the nearest hundredth) , find y if x=4 x = 4 .
How do you find the center and radius for x^2 + y^2 = 36?
2016年8月22日 · The equation here can be expressed in this form, that is (x-0)^2+(y-0)^2=6^2 By comparison with the standard equation. centre = (0 ,0) and radius = 6 Precalculus Science
How do you find all the zeros of # f(x)=x^3+7x^2-6x-72 - Socratic
Use the rational root theorem to help find the first zero, then complete the square to find the other two, giving: 3, -4, -6 f(x) = x^3+7x^2-6x-72 By the rational root theorem, any rational zeros of …