Find the magnitude and direction of the magnetic field in
2018年3月23日 · Point P_1 At point P_1 the magnetic field due to the wire of radius a is directed to the left, and it has a magnitude of {mu_0 2I}/{2 pi r} = mu_0/pi I/r The point P_1 is at …
How do you solve for r in V= (pi r^2)h? - Socratic
2016年4月23日 · How do you determine the amount of liquid a paper cone can hold with a 1.5-inch diameter and a
How do we arrive at the formula for area of a circle as #pir^2#?
2017年2月12日 · Please see below. pi is defined as the ratio of circumference C of a circle to its diameter, which is double the radius r, hence by definition pi=C/(2r and C=2pir There are …
The formula for surface area is S = \pi r^2 + \pi rl where r is the ...
2018年1月19日 · The formula for surface area is #S = \pi r^2 + \pi rl# where #r# is the radius of the semicircle and #l# is the length of the hut.
Solve for specific variable h #S=2pi*rh + 2pi*r^2# - Socratic
2018年2月27日 · There are other approaches" S=2pirh+2pir^2 "reverse the equation to place h on the left side" 2pirh+2pir^2 ...
How do you factor #(pi)r^2 - 4(pi)r+4(pi) - Socratic
2016年10月2日 · =pir^2 Before you factor, you will see that there are two terms which are additive inverses. We end up with one term! pi r^2 -4pir +4pir =pir^2 If you factor anyway - take out a …
What is the Cartesian equivalent of polar coordinates #(2, pi/6)#?
2014年10月2日 · What is the Cartesian equivalent of polar coordinates #(2, pi/6)#? Precalculus Polar Coordinates Converting Coordinates from Polar to Rectangular 1 Answer
What is the Cartesian form of #( 6,-pi/3 )#? - Socratic
2018年7月18日 · How do you find the rectangular coordinates of the point with polar coordinates #(-1,pi/3
How do you find the circumference and area of a circle with
2015年10月5日 · The circumference is 10\pi, the area is 25\pi. You just need to apply the definitions: the circumference is 2\pi*r, where r is the radius. In your case, 2pi*5=10\pi. On the …
How do you graph r=5-2sintheta? - Socratic
2016年11月3日 · This graph is oscillatory about the circle #r = 5#, with relative . amplitude 2 and period #2pi#. A short Table for one period #[0, 2pi] # gives the whole graph that is simply …