SOLUTION: How many 4-digit numbers can be formed by using 2, …
Question 1192828: How many 4-digit numbers can be formed by using 2, 4, 6, 8, 10,12 without repetition of digits? if it is a combination.
SOLUTION: The digits 2,4,6,8, and 0 are used to make five-digit …
Only 6 and 8 are then available for the 1st and 2nd digits, and the 2nd must be larger than the first, so they can only be 68042 and 68240. All the others have 6 and 8 as their 2nd and 4th digits. They are either of the form -6-8- or -8-6-, with 0, 2 and 4 as 1st, 3rd and 5th. The ones of the form -6-8- are 26084, 26480, 46082, and 46280. The ...
b) What is the probability of an even number? - Algebra …
That's 1×3×5 = 15 ways for case 1. Case 2. the first digit is 6. Choose the first digit as 6. That's 1 way. Choose the 2nd digit as any of the 6 digits 2,3,4,5,7,8. That's 6 ways. Having chosen 2 digits, and since no digits can be repeated, there remain only 5 digits to choose from for the 3rd digit. That's 1×6×5 = 30 ways for case 2. Case 3.
Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}
You can put this solution on YOUR website! Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8} Which notation shows the relationship between set C and set D?
SOLUTION: List all the possible subsets of B={2,4,6,8,10}
Question 756929: List all the possible subsets of B={2,4,6,8,10} Answer by tommyt3rd(5050) (Show Source):
SOLUTION: First question : If P=2+4+6+8+...+104 and …
If P=2+4+6+8+...+104 and Q=6+8+10+12+...+106 are sums of arithmetic sequence, determine which is greater, P or Q, and by how much. Second Question: Find a 3 by 3 magic square using the numbers 7,8,9,14,15,16,21,22,and 23. Third question: Suppose there is a pile of quarters, dimes, and pennies with a total of $1.07.
SOLUTION: Use gauss approach to find the sum of 2+4+6+...+100
You can put this solution on YOUR website! 2+4+6+8+10+12+14+...+96+98+100 That has 50 terms, because the sequence of one-half the terms of that series makes the sequence 1,2,3,4,...,48,49,50 Gauss would add those 50 numbers in pairs - the first and the last, the second and the second to last and so on, observing that 2+100=102, 4+98=102, 6+96=102, ...
SOLUTION: Juan threw five darts. the possible scores on the target …
Question 743324: Juan threw five darts. the possible scores on the target were 2,4,6,8,10. each dart hit the target. which of these total scores are you certain is NOT possible? 38, 38, 58, 30, 41, 31, 26, 6, 14, 15 (your solution must include an explanation of why …
SOLUTION: Let: U {0,2,4,6,8,10,12}, A={0,4,8,12}, B={2,10,12], …
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SOLUTION: What are the subsets of {2,4,6,8,10,12,14,16,18}?
9C2 = 36 subsets with 2 elements 9C3 = 84 subsets with 3 elements 9C4 = 126 subsets with 4 elements 9C5 = 126 subsets with 5 elements 9C6 = 84 subsets with 6 elements 9C7 = 36 subsets with 7 elements 9C8 = 9 subsets with 8 elements 9C9 = 1 subset with 9 elements