2017年11月3日 · The basic ("closed") cube is 3" on a side. Each face is broken at the midpoints of all four edges, leaving behind a diamond shape. The four triangles at the four corners therefore each have a and b dimensions of 1.5" and a hypotenuse of 2.12132".

2010年11月21日 · Suppose the service time in minutes at a bank has the exponential distribution with lambda = 1/2. Use the central limit theorem to estimate the probability that the average service time of the first n customers is less than 2.5 minutes. a)n=16 b)n=36 c)n=100 My attempt E(X)=2 Var(X)=4 a)...

2008年10月20日 · Math Help Forum. Math Help Forum with Free Math Help for Math Homework, High School Math, University Math, Statistics, Computer Science, Engineering, Academic STEM Studies

2008年5月22日 · Ron used a calculator to determine that 0.35*2.4=0.84. Ron wants to know why the rule about adding up the number of places to the right of the decimal point doesnt work in this case. Why aren't there 2+1=3 digits to the right of the decimal point in the answer? Is Ron correct that the rule about...

2023年4月28日 · The probabilities are 1) 1/2, 2) 1/4, 3) 1/8, 4) 1/16, 5) 1/32, 6) 1/64, etc. basically \displaystyle\left(\frac{1}{2}\right)^n Multiply each ratio by its probability and add them all up: \displaystyle\sum_{n=1}^\infty\frac{n-1}{n}\cdot\left(\frac{1}{2}\right)^n That's approximately 0.30685. Not sure if this is right, but it's a start.

2007年10月21日 · i pretty much understand linear approximations but i cant seem to solve this problem. if anyone can show me some steps to get me started i would really love that :) Use linear approximation to approximate the number ln(1.01) we know that ln1 = 0

2010年4月19日 · 1) Since they are asking for the chance of getting one out of 4, it would be the bare minimum chance of getting it, so it would be X,X,X, Y. Doing that you get 4/17 or ~23%. (I do not know exactly if this violates the "at least" rule, since it makes sense that you are going for the least common amount).

2009年5月29日 · Determine the number of vectors \begin {bmatrix} x_1 \\ \cdots \\ x_n \end {bmatrix}, such that each x_i is either 0 or 1 and \sum _{i=1}^{n} {x_i} \geq k Click to expand... This is equivalent to finding the probability of k or more successes in n Bernoulli trials with probability of successes 0.5 , then multiplying by the total number of such ...

2009年7月1日 · Morgan left home at 7:00 one morning, determined to make the ten-mile trip to schoool on bicycle for a change. Soon thereafter, a parent noticed forgotten math homework on the kitchen table, got in the car, and tried to catch up with the forgetful child. Morgan had a fifteen minute head start...

2008年2月13日 · 1. draw a rough sketch 2. You can calculate the dotted green line by Cosine rule. The length of this line correspond with the magnitude of Q: |Q| = \sqrt{7^2+10^2-2 \cdot 7 \cdot 10 \cdot \cos(120^{\circ})} \approx 14.798648...\ N 3. To calculate the bearing of Q you have to add the angle \alpha_2 = \alpha to the 120° = bearing of the ...