Ohm (Ω) is the unit of resistance.One ohm is defined as that resistance of an object when a current of 1 Ampere flows through an object having a voltage(potential ...

1/RT = 1/R1 + 1/R2 + 1/R3 … Voltage through the circuit is the same at every point. Individual current draws throughout the circuit add up to the total current draw. Solved Example For You. Q. Find the resistance of an electrical circuit that has voltage supply of 10 Volts and current of 5mA. Solution: V = 10 V, I = 5 mA = 0.005 A. R = V / I

The temperature coefficient of resistance for a wire is 0.00125 C − 1. At 300 K its resistance is 1 ohm. At 300 K its resistance is 1 ohm. The temperature at which the resistance becomes 2 ohm is

Two cells of emf 1.5 V and 2.0 V and internal resistance 2 ohm and 1 ohm respectively have their negative terminals joined by a wire of 6 ohm and positive terminals by another wire of 4 ohm. A third wire of 8 ohm connects mid points of these two wires. Find the potential difference of third wire. 2.3 V; 1.26 V; 1 V; 1.5 V

Resistance of bridge wire=1 ohm/cm x 100cm= 100 Ω 10 Ω and 100 Ω are in parallel = 1000 / 110 Ω = 0.09 Ω Current = 6 9.09 There will be no change in the balancing length if we interchange position of galvanometer and cell.

Two batteries A and B each of e.m.f. 2V are connected in series to an external resistance R = 1 ohm. If the internal resistance of battery A is 1.9 ohm and that of B is 0.9 ohm, what is the potential difference between the terminals of battery A R1 (1) 2V (3) Zero (2) 3.8 V …

Since 1 Ω and 106 Ω are connected in parallel . then the equivalent resistance R will be . 1 R = 1 1 + 1 10 6. R = 10 6 10 6 + 1 ~ 10 6 10 6. R = 1 Ω. Equivalent resistance is 1 Ω (b) 1 Ω and 103 Ω and 160 Ω are in parallel. 1 R = 1 1 + 1 10 3 + 1 10 6. 1 R = 10 6 + 10 3 + 1 10 6. 1 R = 1001001 1000000. R = 0.999 Ω. Therefore ...

1.A cell of emf 4 V and internal resistance 1 ohm is connected to a d.c. source of 10 V through a resistor of 5 ohm. Calculate the terminal voltage across the cell during charging. 2.The potential difference across a cell is 1.8V when a current of 0.5 A is drawn from it. The p.d. falls to 1.6V when a current of 1.0A is drawn.

A galvanometer, together with an unknown resistance in series, is connected across two identical batteries of each 1.5 V. When the batteries are connected in series, the galvanometer records a current of 1 A, and when the batteries are connected in parallel, the current is 0.6 A, then the internal resistance is 1 / x ′ Ω. What is the value ...

A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm all connected in series. If the ammeter has a coil of resistance 480 ohm and as shunt of 20 ohm, the reading in the ammeter will be: