2012年11月26日 · You are looking to prove the following: 1/ (1-cosx) + 1/ (1+cosx) = 2csc 2 x To prove that the left hand side of the equation does in fact equal the right hand side of the equation, we start by solving for the left hand side of the equation.

2018年7月2日 · Ask a question for free Get a free answer to a quick problem. Most questions answered within 4 hours.simplify (1/1-cosx)- (1/1+cosx)

2014年1月5日 · Ask a question for free Get a free answer to a quick problem. Most questions answered within 4 hours.

2014年3月25日 · (cotx-cscx)^2= (1-cosx)/ (1+cosx) Start on the left side and show it equals the right side using trig identities.

2016年4月24日 · Find an Online Tutor Now Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.Simplify (cosx)/ (1-sinx)

2017年5月9日 · (df)/ (dx)=-1/ (1+sinx) We use quotient rule. Let g (x)=cosx and h (x)=1+sinx then (dg)/ (dx)=-sinx and (dh)/ (dx)=cosx and hence using quotient rule (df)/ (dx)= ( (1 ...

2020年4月8日 · Sketch the circle r = 3 cos θ and cardioids r = 1 + cos θ on the same axis. a) Find the area inside both the circle and cardioid. b) Find the arc length of that part of the cardioid outside the circle.

2016年11月12日 · How do you verify sin x + cos x = cos x 1 − tan x + sin x 1 − cot x?

2016年12月15日 · 0 Note that we're in indeterminate form (0/0), so we can use l'Hospital's Rule. L'hospital's Rule states that lim_ (x->c) (g (x))/ (h (x)) = lim_ (x->c) (g' (x))/ (h ...

2016年12月19日 · If you are studying maths, then you should learn the Chain Rule for Differentiation, and practice how to use it: If y = f (x) then f '(x) = dy dx = dy du du dx I was taught to remember that the differential can be treated like a fraction and that the " dx 's" of a common variable will "cancel" (It is important to realise that dy dx isn't a fraction but an operator that …