Data bus: The data bus is an electrical path that connects the cpu,memory and the other hardware devices on the motherboard. the number of wires in the data bus affects the speed at which data can travel between components.Since each wire can transfer one bit at a time therefore,an 8-wire or one byte at a time.

2017年11月8日 · Most modern machines are byte-addressable (8-bit) meaning that each address refers to 1 byte. In this case, assuming that you have an n-bit processor with a matching n-bit address bus (there are cases where these aren't the same, e.g. Pentium processors) the number of memory locations possible is 2^n bytes.

2011年9月25日 · For example, to represent 4 words, you need 4 addresses, 2 raised to 2 is 4, so you need two bits. 00 is the address of the first word, 01 is the address of the second word, 10 is the address of the third word, and 11 is the address of the 4th word.

2011年7月16日 · Any answer referring to the bus size and physical memory is slightly mistaken, since OP's question was about virtual address space not physical address space. For example the supposedly analogous limit on some 386's was a limit on the physical memory they could use, not the virtual address space, which was always a full 32 bits.

2013年3月7日 · The address bus connects the CPU with the main memory. So if the address bus has 32 bits, the max size of the main memory is 2^32 bytes, i.e. 4 GB. The address bus transfers a physical address, and thus the physical address space in this example is 4 GB.

The formula is the highest address-lowest address + 1. For your first problem range1: FD00 0000 to FDFF FFFF, the answer is 00FF FFFF+1=0100 0000H=1 X 16^6= 1 X (2^4)^6=2^24=2^4 x 2^20. For in binary system 2^10= 1024=1K and 2^20=1K x 1 K = 1M then 2^4 x 2^20=16 M.

2022年11月5日 · A memory device has 16 address lines and 64 data lines. Calculate the storage capacity of the memory in bytes and kilobytes. I know that if there are 16 address lines, there are 2^16 = 65,536 addressable locations. How do I use the number of data lines to calculate the storage capacity?

2021年1月2日 · If you have an address bus of width 32, you can access 2 ^ 32 = 4294967296, addresses, which is around 4 GB of RAM memory. That's the reason you can't install more than 4 GB memory on a 32-bit system - because the extra-memory cannot be addressed (the registers have a fixed 32-bit size).

2011年10月14日 · Is the address space a function of the address bus or does it have to do with the microprocessor? Yes, the address space is a function of the address bus though there are tricks you can use to expand how much memory you can use. An example of that is bank switching which gives you more accessible memory but no more address space (multiple ...

2014年9月13日 · If you address bytes like how most modern architectures do then it will give you 4GB. But if you address much larger blocks you will need less bits to address 4GB. For example if you address each 512-byte block (2 9 bytes) you can address 4GB with 23 bits. FAT16 uses 16 bits to address (maximum) 64KB clusters and therefore can address a maximum ...