2016年12月2日 · The number $137$ is a prime number.One of the permutation of $137$ is $173$, which is a prime number. The summation of $137$ digits is $11$ which is again a prime number! My question: Is there a name for this type of numbers? There are some other Properties for $137$ in Wikipedia. I found another Properties such that $137=2^7+2^3+1$ or the only ...

2015年8月6日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

2015年6月10日 · In aviation the 200/20 rule can be used. If your current heading in degree is below 180° e.g. 80° then you add 200 and subtract 20. 80+200=280. 280-20=260.

I need some help with this problem: $$439^{233} \\mod 713$$ I can't calculate $439^{223}$ since it's a very big number, there must be a way to do this. Thanks.

The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $\frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general.

2011年12月16日 · You'll be surprised. The correct probability of winning at least one ticket is around $0.2242$. Assuming exactly one prize is given, your answer of $\frac{1}{160}$ is the pr

2020年3月12日 · What is the exact value of 3.199 E +01 ? Does it mean $3.199\\times10^1$?? I get confused with the notation.

I know how to solve mod using division i.e. $$11 \\mod 7 = 4$$ For this I did a simple division and took its remainder: i.e. $$11 = 7 \\cdot 1 + 4$$ Where $11$ was dividend, $7$ divisor, $1$ quotient...

2022年6月9日 · A solution I got: $10001=11025-1024=105^2-32^2=137\times73$ which are primes. But no way could I have myself figured out that 10001 is difference of those 2 squares. But no way could I have myself figured out that 10001 is difference of those 2 squares.

There are $\frac{205}{250}$ well-prepared students and $\frac{137}{250}$ poorly prepared students who answered a certain item in the exam correctly. The goal is to do a hypothesis test to see whether the given item in the test that is answered correctly can be expected to be at least $15\%$ higher among well-prepared students than among poorly ...