It's easy to find duplicates with one field: SELECT email, COUNT(email) FROM users GROUP BY email HAVING COUNT(email) > 1 So if we have a table ID NAME EMAIL 1 John [email protected] 2 S...

2016年2月9日 · I would like a SQL query for MS Jet 4.0 (MSSql?) to get a count of all the duplicates of each number in a database. The fields are: id (autonum), number (text) I have a database with a lot of numbers. Each number should be returned in numerical order, without duplicates, with a count of all duplicates.

It looks like your current dataset has no duplicates, which makes it a bad representative sample for your question. Are you thinking counting the number of hits in, say ranges of 50, like 400-450, 450-500, 500-550, etc?

2015年1月25日 · SQL Count and group duplicates. Ask Question Asked 12 years, 1 month ago. Modified 10 years ago. Viewed ...

2010年3月25日 · SELECT City, Count(City) As theCount FROM (Select City, State From tblCityStateZips Group By City, State) As C GROUP By City HAVING COUNT Count(City) > 1 This would return all cities, with count, that were contained in more than one state. Greenville 39 Greenwood 2 GreenBriar 3 etc.

2020年5月9日 · I need to assign its duplicate count to a variable. DECLARE @duplicateCount INT; I wrote a query to check duplicates. SELECT COUNT(c.ProductId) FROM @Product c GROUP BY c.ProductId HAVING COUNT(*) > 1 This query returns the following output:

2016年6月30日 · Duplicate problems can often be expressed in terms of EXISTS(the other). SELECT COUNT(*) FROM my_table mt WHERE EXISTS ( SELECT * FROM my_table x WHERE x.case_id = mt.case_id -- exactly the same "keys" AND x.raw_name = mt.raw_name AND x.initials = mt.initials AND x.name = mt.name AND x.judge_id = mt.judge_id AND …

2022年1月19日 · Count Duplicate Data in Column and Display Once Per Row - SQL. Finding duplicate values in a SQL table. The problem with these links and everything I am finding online is that they are all using GROUP BY. Is there a simple, clean way to get the count of each name in the table, and then write the number to a column for each row?

Another way we can use COUNT window function with filter condition to make it which add grouping columns in PARTITION BY part. SELECT s.id, s.name,s.city FROM ( SELECT *,COUNT(*) OVER(PARTITION BY name,city) cnt FROM stuff ) s WHERE cnt > 1 sqlfiddle

2012年9月21日 · If you want to count the actual number of duplicates, use this: SELECT COALESCE(SUM(rows) - count(1), 0) as dupes FROM( SELECT COUNT(1) as rows FROM `yourtable` GROUP BY `name` HAVING rows > 1 ) x What this does is total the duplicates in the group by, but then subtracts the amount of records that have duplicates.